Find the magnetic field at P due to the arran | vedclass

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Question

$\mathrm{B}=\overrightarrow{\mathrm{B}}_{1}+\overrightarrow{\mathrm{B}}_{2}$

$\mathrm{B}=\frac{\mu_{0} \mathrm{I}}{4 \pi \frac{\mathrm{d}}{\sqrt{2}

Vedclass · Accepted Answer

$\frac{{{\mu _0}i}}{{\sqrt 2 \,\pi \,d}}\left( {1 - \frac{1}{{\sqrt 2 }}} \right)\, \otimes $

Vedclass · Answer

$\mathrm{B}=\overrightarrow{\mathrm{B}}_{1}+\overrightarrow{\mathrm{B}}_{2}$

$\mathrm{B}=\frac{\mu_{0} \mathrm{I}}{4 \pi \frac{\mathrm{d}}{\sqrt{2}}}\left(-\sin \frac{\pi}{4}+\sin \frac{\pi}{2}ight) 	imes 2 \otimes$

$\mathrm{B}=\frac{\mu_{0} \mathrm{I}}{2 \pi \frac{\mathrm{d}}{\sqrt{2}}}\left(1-\frac{1}{\sqrt{2}}ight) \otimes$

$\mathrm{B}=\frac{\sqrt{2} \mu_{0} \mathrm{I}}{2 \pi \mathrm{d}}\left(\frac{\sqrt{2}-1}{\sqrt{2}}ight) \otimes$

$	herefore \mathrm{B}=\frac{\mu_{0} \mathrm{I}}{2 \pi \mathrm{d}}(\sqrt{2}-1) \otimes$

$\mathrm{B}=\frac{\mu_{0} \mathrm{i}}{\sqrt{2} \pi \mathrm{d}}\left(1-\frac{1}{\sqrt{2}}ight) \otimes$

Find the magnetic field at $P$ due to the arrangement shown

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