Explain the experiment which demonstrates the magnetic field produced due to a straight long current-carrying wire.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The experiment involves a long,straight current-carrying wire placed perpendicular to the plane of a sheet of paper. $A$ ring of small magnetic compass needles is placed around the wire to map the magnetic field.
$(a)$ When the current flows out of the plane of the paper (represented by a dot),the compass needles align in a counter-clockwise direction.
$(b)$ When the current flows into the plane of the paper (represented by a cross),the compass needles align in a clockwise direction.
$(c)$ If iron filings are sprinkled on the paper around the wire,they arrange themselves in concentric circles,representing the magnetic field lines.
The darkened ends of the needles represent the north poles. The effect of the Earth's magnetic field is assumed to be negligible. This experiment confirms that an electric current flowing through a conductor induces a magnetic field around it,which follows the right-hand thumb rule.

Explore More

Similar Questions

Two long parallel wires separated by $0.1 \ m$ carry currents of $1 \ A$ and $2 \ A$,respectively,in opposite directions. $A$ third current-carrying wire parallel to both of them is placed in the same plane such that it feels no net magnetic force. It is placed at a distance of

Two circular loops $L_1$ and $L_2$ of wire carrying equal and opposite currents are placed parallel to each other with a common axis. The radius of loop $L_1$ is $R_1$ and that of $L_2$ is $R_2$. The distance between the centres of the loops is $\sqrt{3} R_1$. The magnetic field at the centre of $L_2$ shall be zero if

Two long straight wires are placed along the $x$-axis and $y$-axis. They carry currents $I_1$ and $I_2$ respectively. The equation of the locus of points with zero magnetic induction in the magnetic field produced by them is:

$A$ current-carrying loop $ABCD$ has two circular arcs $AD$ and $BC$ with radii $1 \text{ cm}$ and $2 \text{ cm}$ respectively,as shown in the figure. The two arcs $AD$ and $BC$ subtend a common angle of $30^{\circ}$ at the centre $O$. If the current flowing in the loop is $\frac{1.2}{\pi} \text{ A}$,then the magnitude of the net magnetic field at $O$ is (Given $\mu_0 = 4\pi \times 10^{-7} \text{ T m/A}$): (in $\mu \text{T}$)

$A$ Helmholtz coil has a pair of loops,each with $N$ turns and radius $R$. They are placed coaxially at a distance $R$ apart,and the same current $I$ flows through the loops in the same direction. The magnitude of the magnetic field at $P$,the midpoint between the centers $A$ and $C$,is given by (Refer to figure):

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo