Explain experiment which produced magnetic field due to straight long current carrying wire.
Explain experiment which produced magnetic field due to straight long current carrying wire.
One straight long current carrying wire which is kept perpendicular to the plane of paper. The ring of compass needles surrounds the wire.
The magnetic field due to a straight long current-carrying wire. The wire is perpendicular to the plane of the paper. A ring of compass needles surrounds the wire. The orientation of the needles is shown when $(a)$ the current emerges out of the plane of the paper, $(b)$ the current moves into the plane of the paper. $(c)$ The arrangement of iron filings around the wire. The darkened ends of the needle represent north poles. The effect of the earth's magnetic field is neglected.
When current emerges out of the plane of the paper the orientation of the needles is shown in figure $(a)$.
When current moves into the plane of paper the orientation of the needle is shown in figure $(b)$.
The darkened ends of the needle represent north poles.
If iron ore is spreaded around it, then the arrangement of iron fillings around the wire as shown in figure $(c)$.
So, from this experiment we can conclude that when current is passing through conducting wire, magnetic field induced around it.
Similar Questions
As shown in the figure, two infinitely long, identical wires are bent by $90^o$ and placed in such a way that the segments $LP$ and $QM$ are along the $x-$ axis, while segments $PS$ and $QN$ are parallel to the $y-$ axis. If $OP = OQ = 4\, cm$, and the magnitude of the magnetic field at $O$ is $10^{-4}\, T$, and the two wires carry equal current (see figure), the magnitude of the current in each wire and the direction of the magnetic field at $O$ will be $(\mu_ 0 = 4\pi \times10^{-7}\, NA^{-2})$
As shown in the figure, two infinitely long, identical wires are bent by $90^o$ and placed in such a way that the segments $LP$ and $QM$ are along the $x-$ axis, while segments $PS$ and $QN$ are parallel to the $y-$ axis. If $OP = OQ = 4\, cm$, and the magnitude of the magnetic field at $O$ is $10^{-4}\, T$, and the two wires carry equal current (see figure), the magnitude of the current in each wire and the direction of the magnetic field at $O$ will be $(\mu_ 0 = 4\pi \times10^{-7}\, NA^{-2})$
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