A helium nucleus makes a full rotation in a c | vedclass

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Question

(b) $i = \frac{q}{T} = \frac{{2 	imes 1.6 	imes {{10}^{ - 19}}}}{2} = 1.6 	imes {10^{ - 19}}A$
$	herefore \,B = \frac{{{\mu _o}i}}{{2r}} = \frac{

Vedclass · Accepted Answer

${10^{ - 19}}{\mu _0}$

Vedclass · Answer

(b) $i = \frac{q}{T} = \frac{{2 	imes 1.6 	imes {{10}^{ - 19}}}}{2} = 1.6 	imes {10^{ - 19}}A$
$	herefore \,B = \frac{{{\mu _o}i}}{{2r}} = \frac{{{\mu _o} 	imes 1.6 	imes {{10}^{ - 19}}}}{{2 	imes 0.8}} = {\mu _o} 	imes {10^{ - 19}}$

A helium nucleus makes a full rotation in a circle of radius $0.8$ metre in two seconds. The value of the magnetic field $B$ at the centre of the circle will be

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