$A$ helium nucleus makes a full rotation in a circle of radius $0.8 \ m$ in $2 \ s$. The value of the magnetic field $B$ at the centre of the circle will be
- A$\frac{10^{-19}}{\mu_0}$
- B$10^{-19} \mu_0$
- C$2 \times 10^{-10} \mu_0$
- D$\frac{2 \times 10^{-10}}{\mu_0}$
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