(B) We are given the condition $x_{1} = 1, x_{2} = 0, x_{3} = 0$. We evaluate the given options: For option $B$: $x_{1} \cdot x_{2}' = 1 \cdot (0)' =

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(B) We are given the condition $x_{1} = 1, x_{2} = 0, x_{3} = 0$. We evaluate the given options: For option $B$: $x_{1} \cdot x_{2}' = 1 \cdot (0)' = 1 \cdot 1 = 1$. Thus,the function $f(x_{1}, x_{2}, x_{3}) = x_{1} \cdot x_{2}'$ satisfies the condition.

Class 11 Mathematics Mathematical Reasoning Mathematical logic

Easy

Find the function $f(x_{1}, x_{2}, x_{3})$ that satisfies $f(x_{1}, x_{2}, x_{3}) = 1$ at $x_{1} = 1, x_{2} = 0, x_{3} = 0$.

MHT CET 2009 All MHT CET

A
$x_{1}' \cdot x_{2}$
B
$x_{1} \cdot x_{2}'$
C
$(x_{1} + x_{2} + x_{3})' \cdot x_{2}$
D
$(x_{1}' + x_{3}) \cdot x_{3}$

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Find the function $f(x_{1}, x_{2}, x_{3})$ that satisfies $f(x_{1}, x_{2}, x_{3}) = 1$ at $x_{1} = 1, x_{2} = 0, x_{3} = 0$.

Similar Questions

Among the two statements:$(S1): (p \Rightarrow q) \wedge (q \wedge (\sim q))$ is a contradiction and$(S2): (p \wedge q) \vee ((\sim p) \wedge q) \vee (p \wedge (\sim q)) \vee ((\sim p) \wedge (\sim q))$ is a tautology.

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Among the two statements:
$(S1): (p \Rightarrow q) \wedge (q \wedge (\sim q))$ is a contradiction and
$(S2): (p \wedge q) \vee ((\sim p) \wedge q) \vee (p \wedge (\sim q)) \vee ((\sim p) \wedge (\sim q))$ is a tautology.