Check whether the following is a quadratic eq | vedclass

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(B) Expand both sides of the equation:$(x-2)(x+1) = x^2 + x - 2x - 2 = x^2 - x - 2$$(x-1)(x+3) = x^2 + 3x - x - 3 = x^2 + 2x - 3$Equating both sides:$

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) Expand both sides of the equation:$(x-2)(x+1) = x^2 + x - 2x - 2 = x^2 - x - 2$$(x-1)(x+3) = x^2 + 3x - x - 3 = x^2 + 2x - 3$Equating both sides:$x^2 - x - 2 = x^2 + 2x - 3$Subtract $x^2$ from both sides:$-x - 2 = 2x - 3$Rearranging the terms:$3x - 1 = 0$Since the highest power of the variable $x$ is $1$,it is not of the form $ax^2 + bx + c = 0$ (where $a 
eq 0$).Therefore,the given equation is not a quadratic equation.

Check whether the following is a quadratic equation:
$(x-2)(x+1)=(x-1)(x+3)$

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Check whether the following is a quadratic equation:$(x-2)(x+1)=(x-1)(x+3)$