Find the area of the shaded field shown in $Fig.$

1061-40

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In a figure, join $ED$

From figure, radius of semi-circle $D F E, r=6-4=2 \,m$

Now, area of rectangle $A B C D=B C \times A B=8 \times 4=32\, m ^{2}$

and area of semi-circle $DFE$ $=\frac{\pi r^{2}}{2}=\frac{\pi}{2}(2)^{2}=2 \pi \, m ^{2}$

$\therefore$ Area of shaded region $=$ Area of rectangle $A B C D+$ Area of semi-circle $DFE$

$=(32+2 \pi) \,m ^{2}$

1061-s40

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