Find the HCF and LCM of 6, 72 and 120 using t | vedclass

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(C) We have the prime factorisation of the numbers:$6 = 2^1 	imes 3^1$$72 = 2^3 	imes 3^2$$120 = 2^3 	imes 3^1 	imes 5^1$To find the $HCF$,we take

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$6; 360$

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(C) We have the prime factorisation of the numbers:$6 = 2^1 	imes 3^1$$72 = 2^3 	imes 3^2$$120 = 2^3 	imes 3^1 	imes 5^1$To find the $HCF$,we take the product of the smallest power of each common prime factor:$HCF(6, 72, 120) = 2^1 	imes 3^1 = 6$To find the $LCM$,we take the product of the greatest power of each prime factor involved in the numbers:$LCM(6, 72, 120) = 2^3 	imes 3^2 	imes 5^1 = 8 	imes 9 	imes 5 = 360$Thus,the $HCF$ is $6$ and the $LCM$ is $360$.

Find the $HCF$ and $LCM$ of $6, 72$ and $120$ using the prime factorisation method.

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