Find the G.C.D. of 8(x^{3}-x^{2}+x) and 28(x^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) First,factorize the given expressions:$p(x) = 8(x^{3}-x^{2}+x) = 2^{3} \cdot x \cdot (x^{2}-x+1)$$q(x) = 28(x^{3}+1) = 2^{2} \cdot 7 \cdot (x+1)(x

Vedclass · Accepted Answer

$4(x^{2}-x+1)$

Vedclass · Answer

(B) First,factorize the given expressions:$p(x) = 8(x^{3}-x^{2}+x) = 2^{3} \cdot x \cdot (x^{2}-x+1)$$q(x) = 28(x^{3}+1) = 2^{2} \cdot 7 \cdot (x+1)(x^{2}-x+1)$Next,identify the common factors:The numerical $G.C.D.$ of $8$ and $28$ is $2^{2} = 4$.The common polynomial factor is $(x^{2}-x+1)$.Therefore,the required $G.C.D.$ is $4(x^{2}-x+1)$.

Find the $G.C.D.$ of $8(x^{3}-x^{2}+x)$ and $28(x^{3}+1)$.

Similar Questions

If $(x-4)$ is the $G.C.D.$ of $x^{2}-x-12$ and $x^{2}-mx-8$,find the value of $m$.

For what value of $a,$ the $G.C.D.$ of $x^{2}-2x-24$ and $x^{2}-ax-6$ is $(x-6)$?

Find the $G.C.D.$ of the polynomials $6 x^{2}+11 x+3$ and $2 x^{2}+x-3$.

The $H.C.F.$ of two expressions $p$ and $q$ is $1$. Their $L.C.M.$ is

Find the $G.C.D.$ of $4x^4 + y^4$,$2x^3 - xy^2 - y^3$,and $2x^2 + 2xy + y^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module