Find out the following in the electric circuit given in figure
$(a)$ Effective resistance of two $8\, \Omega$ resistors in the combination.
$(b)$ Current flowing through $4\, \Omega$ resistor.
$(c)$ Potential difference across $4\, \Omega$ resistor.
$(d)$ Power dissipated in $4\, \Omega$ resistor.
$(e)$ Difference in ammeter readings, if any.
$(a)$ $R _{ P }=\frac{ R _{1} R _{2}}{ R _{1}+ R _{2}}=\frac{8 \times 8}{8+8}=\frac{64}{16}=4 \Omega$
$(b)$ Net resistance of the circuit $R _{ S }=4+4=8 \Omega$ Therefore, current in the circuit $I=V / R_{S}$
$=8 / 8=1 A$
$(c)$ $V = IR =1 \times 4=4 V$
$(d)$ $P=I^{2} R=(1)^{2} \times 4=4 W$
$(e)$ No difference as same current flows through each element in a series circuit.
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