Find out the following in the electric circuit given in figure

$(a)$ Effective resistance of two $8\, \Omega$ resistors in the combination.

$(b)$ Current flowing through $4\, \Omega$ resistor.

$(c)$ Potential difference across $4\, \Omega$ resistor.

$(d)$ Power dissipated in $4\, \Omega$ resistor.

$(e)$ Difference in ammeter readings, if any.

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$(a)$ $R _{ P }=\frac{ R _{1} R _{2}}{ R _{1}+ R _{2}}=\frac{8 \times 8}{8+8}=\frac{64}{16}=4 \Omega$

$(b)$ Net resistance of the circuit $R _{ S }=4+4=8 \Omega$ Therefore, current in the circuit $I=V / R_{S}$

$=8 / 8=1 A$

$(c)$ $V = IR =1 \times 4=4 V$

$(d)$ $P=I^{2} R=(1)^{2} \times 4=4 W$

$(e)$ No difference as same current flows through each element in a series circuit.

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