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Question

(A) In the given circuit,there are two branches connected between points $A$ and $B$.Branch $1$ consists of two resistors of $4 \, \Omega$ each,connec

Vedclass · Accepted Answer

$4 \, \Omega$

Vedclass · Answer

(A) In the given circuit,there are two branches connected between points $A$ and $B$.Branch $1$ consists of two resistors of $4 \, \Omega$ each,connected in series. The equivalent resistance of this branch is $R_1 = 4 \, \Omega + 4 \, \Omega = 8 \, \Omega$.Branch $2$ consists of a single resistor of $8 \, \Omega$ connected directly between $A$ and $B$.Now,these two branches ($R_1 = 8 \, \Omega$ and $R_2 = 8 \, \Omega$) are connected in parallel.The equivalent resistance $R_{eq}$ is given by the formula: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$.Substituting the values: $\frac{1}{R_{eq}} = \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}$.Therefore,$R_{eq} = 4 \, \Omega$.

The equivalent resistance between points $A$ and $B$ of the following electric circuit will be $.........$

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