Find magnetic field at $O$
$\frac{{5{\mu _0}i\theta }}{{24\pi r}}$
$\frac{{{\mu _0}i\theta }}{{24\pi r}}$
$\frac{{11{\mu _0}i\theta }}{{24\pi r}}$
Zero
The magnetic field at the centre of a wire loop formed by two semicircular wires of radii $R_1=2 \pi\ \mathrm{m}$ and $R_2=4 \pi\ \mathrm{m}$ carrying current $I=4 \mathrm{~A}$ as per figure given below is $\alpha \times 10^{-7} \mathrm{~T}$. The value of $\alpha$ is___________ (Centre $\mathrm{O}$ is common for all segments)
The magnetic induction at the centre $O$ in the figure shown is
Two circular coils $X$ and $Y$, having equal number of turns, carry equal currents in the same sense and subtend same solid angle at point $O$. If the smaller coil, $X$ is midway between $O$ and $Y$, then if we represent the magnetic induction due to bigger coil $Y$ at $O$ as $BY$ and that due to smaller coil $X$ at $O$ as $BX$ , then
Which of the following gives the value of magnetic field according to, Biot-Savart’s law’
A cell is connected between two points of a uniformly thick circular conductor. The magnetic field at the centre of the loop will be