Find $p(0), p(1), p(-2)$ for the following polynomials:
$p(y)=(y+2)(y-2)$
Find $p(0), p(1), p(-2)$ for the following polynomials:
$p(y)=(y+2)(y-2)$
We have $p(y)=(y+2)(y-2)=y^{2}-4$
$\therefore$ $p(0)=(0)^{2}-4$
$=0-4=-4$
And, $p(1)=(1)^{2}-4$
$=1-4=-3$
And, $\quad p(-2)=(-2)^{2}-4$
$=4-4=0$
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