Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(x) = (x - 1)(x + 1)$.
(N/A) Given the polynomial $p(x) = (x - 1)(x + 1)$.
To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = (0 - 1)(0 + 1) = (-1)(1) = -1$.
To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = (1 - 1)(1 + 1) = (0)(2) = 0$.
To find $p(2)$,substitute $x = 2$ into the polynomial:
$p(2) = (2 - 1)(2 + 1) = (1)(3) = 3$.
To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = (0 - 1)(0 + 1) = (-1)(1) = -1$.
To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = (1 - 1)(1 + 1) = (0)(2) = 0$.
To find $p(2)$,substitute $x = 2$ into the polynomial:
$p(2) = (2 - 1)(2 + 1) = (1)(3) = 3$.
Explore More
Similar Questions
Factorise the following: $27 y^{3}+125 z^{3}$
Easy
View SolutionWrite the degree of each of the following polynomials:
$(i)$ $5t - \sqrt{7}$
$(ii)$ $3$
$(i)$ $5t - \sqrt{7}$
$(ii)$ $3$
Easy
View SolutionVerify whether the following is a zero of the polynomial indicated against it:
$p(x) = 3x + 1, \, x = -\frac{1}{3}$
$p(x) = 3x + 1, \, x = -\frac{1}{3}$
Easy
View SolutionVerify that $x^{3}+y^{3}+z^{3}-3xyz = \frac{1}{2}(x+y+z)[(x-y)^{2}+(y-z)^{2}+(z-x)^{2}]$
Difficult
View SolutionWrite the coefficients of $x^2$ in each of the following:
$(i)$ $2+x^2+x$
$(ii)$ $2-x^2+x^3$
$(i)$ $2+x^2+x$
$(ii)$ $2-x^2+x^3$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo