Find $p(0)$, $p(1)$ and $p(2)$ for  of the following polynomials : $p(x)=(x-1)(x+1)$

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$p ( x )=( x -1)( x +1)$

$\because$ $p ( x )=( x -1)( x +1)$

$\therefore$ $p (0)=(0-1)(0+1)=-1 \times 1=-\,1$

$p (1)=(1-1)(1+1)=(0)(2)=0$

$p (2)=(2-1)(2+1)=(1)(3)=3$

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