Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=3 x+1, \,\,x=-\,\frac{1}{3}$
If $x=\frac{-1}{3}$ is a zero of given polynomial $p(x)=3 x+1,$ then $p\left(-\frac{1}{3}\right)$ should be $0 .$
Here, $p\left(\frac{-1}{3}\right)=3\left(\frac{-1}{3}\right)+1=-1+1=0$
Therefore, $x=\frac{-\,1}{3}$ is a zero of the given polynomial.
Which of the following expressions are polynomials in one variable and which are not ? State reasons for your answer. $x^{10}+y^{3}+t^{50}$
Use suitable identities to find the products : $\left(y^{2}+\frac{3}{2}\right)\left(y^{2}-\frac{3}{2}\right)$
Write the following cubes in the expanded form : $(5 p-3 q)^{3}$
Use suitable identities to find the products : $(3-2 x)(3+2 x)$
Expand each of the following, using suitable identities : $(2 x-y+z)^{2}$