Factorise 49 x^{2}-42 x+9. | vedclass

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Question

(B) To factorise the expression $49 x^{2}-42 x+9$,we observe that it follows the algebraic identity $a^{2}-2ab+b^{2} = (a-b)^{2}$.Here,$a^{2} = 49 x^{

Vedclass · Accepted Answer

$(7x-3)(7x-3)$

Vedclass · Answer

(B) To factorise the expression $49 x^{2}-42 x+9$,we observe that it follows the algebraic identity $a^{2}-2ab+b^{2} = (a-b)^{2}$.Here,$a^{2} = 49 x^{2} = (7 x)^{2}$,so $a = 7 x$.And $b^{2} = 9 = (3)^{2}$,so $b = 3$.Now,check the middle term: $-2ab = -2(7 x)(3) = -42 x$.Since the expression matches the identity,we can write:$49 x^{2}-42 x+9 = (7 x)^{2}-2(7 x)(3)+(3)^{2} = (7 x-3)^{2}$.Thus,the factors are $(7 x-3)(7 x-3)$.

Factorise $49 x^{2}-42 x+9$.

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