Factorise $8 x^{3}+27 y^{3}+125 z^{3}-90 x y z$.

(N/A) The given expression is of the form $a^{3}+b^{3}+c^{3}-3 a b c$,where $a = 2x$,$b = 3y$,and $c = 5z$.
Using the algebraic identity $a^{3}+b^{3}+c^{3}-3 a b c = (a+b+c)(a^{2}+b^{2}+c^{2}-a b-b c-c a)$:
Substitute $a = 2x$,$b = 3y$,and $c = 5z$ into the identity:
$8 x^{3}+27 y^{3}+125 z^{3}-3(2x)(3y)(5z) = (2x+3y+5z)((2x)^{2}+(3y)^{2}+(5z)^{2}-(2x)(3y)-(3y)(5z)-(5z)(2x))$
$= (2x+3y+5z)(4x^{2}+9y^{2}+25z^{2}-6xy-15yz-10zx)$.