Factorise of the following : $27 y^{3}+125 z^{3}$
Factorise of the following : $27 y^{3}+125 z^{3}$
Using the identity $\left(x^{3}+y^{3}\right)=(x+y)\left(x^{2}-x y+y^{2}\right),$ we have
$27 y^{3}+125 z^{3} =(3 y)^{3}+(5 z)^{3}=(3 y+5 z)\left[(3 y)^{2}-(3 y)(5 z)+(5 z)^{2}\right]$
$=(3 y+5 z)\left(9 y^{2}-15 y z+25 z^{2}\right)$
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