Evaluate 105 times 106 without multiplying di | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To evaluate $105 	imes 106$ without direct multiplication,we can express the numbers as $(100 + 5)$ and $(100 + 6)$.Using the algebraic identity

Vedclass · Accepted Answer

$11130$

Vedclass · Answer

(A) To evaluate $105 	imes 106$ without direct multiplication,we can express the numbers as $(100 + 5)$ and $(100 + 6)$.Using the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$,where $x = 100$,$a = 5$,and $b = 6$:$105 	imes 106 = (100 + 5)(100 + 6)$$= (100)^2 + (5 + 6)(100) + (5 	imes 6)$$= 10000 + 11(100) + 30$$= 10000 + 1100 + 30$$= 11130$

Evaluate $105 \times 106$ without multiplying directly.

Similar Questions

Factorise : $x^{3}-3 x^{2}-9 x-5$

Verify whether the following are zeroes of the polynomial indicated against them:
$p(x) = x^{2} - 1, x = 1, -1$

Factorise the following using appropriate identities: $9x^{2}+6xy+y^{2}$

Find the remainder when $x^4+x^3-2x^2+x+1$ is divided by $x-1$.

Determine which of the following polynomials has $(x + 1)$ as a factor: $x^{3} + x^{2} + x + 1$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module