Factorise : 4 x^{2}+4 x y-3 y^{2} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To factorise the quadratic expression $4 x^{2}+4 x y-3 y^{2}$,we use the splitting the middle term method.We need to find two numbers whose produc

Vedclass · Accepted Answer

$(2x + 3y)(2x - y)$

Vedclass · Answer

(B) To factorise the quadratic expression $4 x^{2}+4 x y-3 y^{2}$,we use the splitting the middle term method.We need to find two numbers whose product is $(4) 	imes (-3) = -12$ and whose sum is $4$.These two numbers are $6$ and $-2$.Now,rewrite the middle term $4xy$ as $6xy - 2xy$:$4 x^{2}+6 x y-2 x y-3 y^{2}$Group the terms:$= (4 x^{2}+6 x y) - (2 x y+3 y^{2})$Factor out the common terms from each group:$= 2 x(2 x+3 y)-y(2 x+3 y)$Finally,factor out the common binomial $(2 x+3 y)$:$= (2 x+3 y)(2 x-y)$

Factorise $: 4 x^{2}+4 x y-3 y^{2}$

Similar Questions

$4x^{2} - 20x + 25 = (\ldots \ldots \ldots)^{2}$

Evaluate $77 \times 83$.

Find the value of $x^{3}+y^{3}-12xy+64$,when $x+y=-4$.

Factorise:
$a^{3}-8 b^{3}-64 c^{3}-24 a b c$

Expand $(x+4)(x+9)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module