Explain formation of $\mathrm{H}_{2}$ and energy level diagram of $\mathrm{H}_{2}$ molecule.
$1 s$ atomic orbitals on two atoms (e.g. hydrogen form two molecular orbitals designated as $\sigma 1 s$ and $\sigma^{*} 1 s$ is.
$\sigma 1 s$ is bonding molecular orbital (BMO) and $\sigma 1 s$ is Antibonding molecular orbital (ABMO). Energy of
$\sigma 1 s$ is $<$ Energy of atomic orbital is $1 s<\sigma^{*} 1 s$.
(Energy of $\sigma 1 s+$ Energy of $\sigma^{*} 1 s$ ) $=($ Edition of energy of two $1 s)$
The energy diagram of $1 s, \sigma 1 s$ and $\sigma^{*} 1 s$ is as under.
Where, $\mathrm{MO}=$ molecular orbitals, $\sigma 1 s=\mathrm{BMO}$
$\mathrm{AO}=\text { Atomic orbitals, } \sigma 1 s=\mathrm{ABMO}$
Two $MO$, $\sigma 1 s$ and $\sigma^{*} 1 s$ are formed by overlapping of two $1 s$. Its figure is as under.
The total number of species from the following in which one unpaired electron is present, is . . . . . . $\mathrm{N}_2, \mathrm{O}_2, \mathrm{C}_2^{-}, \mathrm{O}_2^{-}, \mathrm{O}_2^{2-}, \mathrm{H}_2^{+}, \mathrm{CN}^{-}, \mathrm{He}_2^{+}$
In the following the correct bond order sequence is :
Given below are two statements:
Statement $(I)$ : A $\pi$ bonding $MO$has lower electron density above and below the inter-nuclear asix.
Statement $(II)$ : The $\pi^*$ antibonding $MO$ has a node between the nucles.In the light of the above statements, choose the most appropriate answer from the options given below:
Which of the following would have same magnetic nature whether $sp$ mixing is operative or not?
Which of the following is paramagnetic