Explain the formation of $H_{2}$ and the energy level diagram of the $H_{2}$ molecule.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The $1s$ atomic orbitals on two hydrogen atoms overlap to form two molecular orbitals,designated as $\sigma 1s$ and $\sigma^{*} 1s$.
$\sigma 1s$ is the bonding molecular orbital $(BMO)$ and $\sigma^{*} 1s$ is the antibonding molecular orbital $(ABMO)$.
The energy order is: Energy of $\sigma 1s < $ Energy of atomic orbital $1s < $ Energy of $\sigma^{*} 1s$.
The sum of the energies of the two molecular orbitals is equal to the sum of the energies of the two $1s$ atomic orbitals.
The energy level diagram for the formation of $H_{2}$ from two $H$ atoms is shown below.
$AO =$ Atomic orbitals,$MO =$ Molecular orbitals,$BMO =$ Bonding molecular orbital,$ABMO =$ Antibonding molecular orbital.
The formation of these molecular orbitals by the linear combination of atomic orbitals $(LCAO)$ is represented as:
$(i)$ $ABMO$ $(\sigma^{*} 1s)$: Formed by the subtractive overlap of two $1s$ orbitals.
(ii) $BMO$ $(\sigma 1s)$: Formed by the additive overlap of two $1s$ orbitals.

Explore More

Similar Questions

Which of the following species has the highest bond order?

Bond order is an inverse measure of

The species,which has the bond order same as that of $F_2$ molecule is

If the magnetic moment of a dioxygen species is $1.73 \; B.M$,it may be

According to molecular orbital theory,the total number of bonding electron pairs in $O_2$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo