Expand the following:

$(4 a-b+2 c)^{2}$

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$(4 a-b+2 c)^{2}=(4 a)^{2}+(-b)^{2}+(2 c)^{2}+2(4 a)(-b)+2(-b)(2 c)+2(2 c)(4 a)$

$\left[\because a^{2}+b^{2}+c^{2}+2 a b+2 b c+2 c a=(a+b+c)^{2}\right]$

$=16 a^{2}+b^{2}+4 c^{2}-8 a b-4 a c+16 c a$

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