(D) To evaluate $(98)^{2}$,we can express $98$ as $(100 - 2)$.Using the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$,where $a = 100$ and $b

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(D) To evaluate $(98)^{2}$,we can express $98$ as $(100 - 2)$.Using the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$,where $a = 100$ and $b = 2$:$(100 - 2)^{2} = (100)^{2} - 2(100)(2) + (2)^{2}$$= 10000 - 400 + 4$$= 9600 + 4$$= 9604$.

Class 9 Mathematics Polynomials Mix Examples - Polynomials

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Evaluate $(98)^{2}$.

A
$9801$
B
$9602$
C
$7463$
D
$9604$

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Evaluate $(98)^{2}$.

Similar Questions

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Find the following product :
$(2 x-y+3 z)(4 x^{2}+y^{2}+9 z^{2}+2 x y+3 y z-6 x z)$

Find the value of the following polynomial at the indicated value of the variable:
$p(x) = x^{2} + 5x - 24$ at $x = 3$

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$4 x^{2}+20 x+25$