The equation of a line passing through the origin and perpendicular to the line joining $(a, 0)$ and $(-a, 0)$ is

Find the equation of the line passing through the point $(1, 2)$ and perpendicular to the line $y = 3x - 1$.

The equation of a line,whose perpendicular distance from the origin is $7$ units and the angle,which the perpendicular to the line from the origin makes,is $120^{\circ}$ with the positive $X$-axis,is

If $p = a_1 x + b_1 y + k_1 = 0$,$q = a_2 x + b_2 y + k_2 = 0$ and $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{k_1}{k_2}$,then the curve $p + c q = 0$ is

The equation of the line passing through the point $(-1, 3)$ in symmetrical form,when the angle made by the line with the positive direction of the $X$-axis is $120^{\circ}$,is given by:

The $y$-intercept of the line passing through $A(6, 1)$ and perpendicular to the line $x - 2y = 4$ is: