The y-intercept of the line passing through A | vedclass

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(B) The given line is $x - 2y = 4$,which can be written as $2y = x - 4$ or $y = \frac{1}{2}x - 2$. The slope of this line is $m_1 = \frac{1}{2}$.Since

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(B) The given line is $x - 2y = 4$,which can be written as $2y = x - 4$ or $y = \frac{1}{2}x - 2$. The slope of this line is $m_1 = \frac{1}{2}$.Since the required line is perpendicular to the given line,its slope $m_2$ must satisfy $m_1 	imes m_2 = -1$. Thus,$m_2 = -2$.The equation of the line passing through $A(6, 1)$ with slope $m_2 = -2$ is given by $y - y_1 = m_2(x - x_1)$.Substituting the values,we get $y - 1 = -2(x - 6)$.$y - 1 = -2x + 12$.$2x + y = 13$.To find the $y$-intercept,we set $x = 0$ in the equation $2x + y = 13$.$2(0) + y = 13 \Rightarrow y = 13$.Therefore,the $y$-intercept of the line is $13$.

The $y$-intercept of the line passing through $A(6, 1)$ and perpendicular to the line $x - 2y = 4$ is:

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