Electrostatic force between two identical charges placed in vacuum at a distance of $r$ is $F$. $A$ slab of width $\frac{r}{5}$ and dielectric constant $9$ is inserted between these two charges. The new force between the charges is:

  • A
    $F$
  • B
    $9F$
  • C
    $\frac{25}{81} F$
  • D
    $\frac{25}{16} F$

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