Two identical balls having like charges and p | vedclass

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Question

Suppose the balls having charge $Q_{1}$ and $Q_{2}$ Intially$:$

$F^{\prime}=\frac{\left(k \frac{Q_{1}+Q_{2}}{2}\right)^{2}}{\left(\frac{r}{2}\right

Vedclass · Accepted Answer

$2$

Vedclass · Answer

Suppose the balls having charge $Q_{1}$ and $Q_{2}$ Intially$:$

$F^{\prime}=\frac{\left(k \frac{Q_{1}+Q_{2}}{2}\right)^{2}}{\left(\frac{r}{2}\right)^{2}}=\frac{k\left(Q_{1}+Q_{2}\right)^{2}}{r^{2}}$

It is given that $F=4.5 F$ so $\frac{\left(Q_{1}+Q_{2}\right)^{2}}{r^{2}}=4.5 k \frac{Q_{1} Q_{2}}{r^{2}}$

$\Rightarrow\left(Q_{1}+Q_{2}\right)^{2}=4.5 Q_{1} Q_{2}$

On solving it gives $\frac{Q_{1}}{Q_{2}}=\frac{2}{1}$

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