Electrical field intensity due to an electric dipole on its axis at distance $x$ $(x \gg a)$ and on the equatorial line at distance $y$ $(y \gg a)$ are same. What is the ratio of $x$ and $y$?

Six charges are placed at the vertices of a regular hexagon as shown in the figure. The electric field on the line passing through point $O$ and perpendicular to the plane of the figure at a distance of $x (>> a)$ from $O$ is

Obtain the expression for the torque acting on an electric dipole in a uniform external electric field.

For a short dipole placed at origin $O$,the dipole moment $P$ is along the $x$-axis,as shown in the figure. If the electric potential and electric field at point $A$ (at distance $r$ on the $x$-axis) are $V_0$ and $E_0$,respectively,then the correct combination of the electric potential and electric field,respectively,at point $B$ (at distance $2r$ on the $y$-axis) is given by

$A$ dipole is placed in a uniform electric field,its potential energy will be minimum when the angle between its axis and field is

An electric dipole of moment $p$ is placed at the origin along the $x$-axis. The electric field at a point $P$,whose position vector makes an angle $\theta$ with the $x$-axis,will make an angle $\phi$ with the $x$-axis. If $\tan \alpha = \frac{1}{2} \tan \theta$,where $\alpha$ is the angle between the electric field vector and the position vector,then the angle $\phi$ that the electric field makes with the $x$-axis is: