An electric dipole of moment $p$ is placed at the origin along the $x$-axis. The electric field at a point $P$,whose position vector makes an angle $\theta$ with the $x$-axis,will make an angle $\phi$ with the $x$-axis. If $\tan \alpha = \frac{1}{2} \tan \theta$,where $\alpha$ is the angle between the electric field vector and the position vector,then the angle $\phi$ that the electric field makes with the $x$-axis is:

  • A
    $\alpha$
  • B
    $\theta$
  • C
    $\theta + \alpha$
  • D
    $\theta + 2\alpha$

Explore More

Similar Questions

$A$ dipole with two electric charges of $2 \ \mu C$ magnitude each,with separation distance $0.5 \ \mu m$,is placed between the plates of a capacitor such that its axis is parallel to an electric field established between the plates when a potential difference of $5 \ V$ is applied. Separation between the plates is $0.5 \ mm$. If the dipole is rotated by $30^{\circ}$ from the axis,it tends to realign in the direction due to a torque. The value of torque is $:$

If the electric field intensity at a distance $x$ on the axis of a dipole is equal to the electric field intensity at a distance $y$ on its equatorial line,then the ratio $x:y$ is:

Difficult
View Solution

Two identical electric point dipoles have dipole moments $\overrightarrow{p}_{1} = p\hat{i}$ and $\overrightarrow{p}_{2} = -p\hat{i}$ and are held on the $x$-axis at a distance $'a'$ from each other. When released,they move along the $x$-axis with the direction of their dipole moments remaining unchanged. If the mass of each dipole is $'m'$,their speed when they are infinitely far apart is

$A$ dipole is placed in an electric field as shown. In which direction will it move?

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: If an electric dipole of dipole moment $30 \times 10^{-5} \, Cm$ is enclosed by a closed surface,the net flux coming out of the surface will be zero.
Reason $R$: An electric dipole consists of two equal and opposite charges.
In the light of the above statements,choose the correct answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo