A charged oil drop is suspended in a uniform field of $3 \times$ $10^{4} V / m$ so that it neither falls nor rises. The charge on the drop will be $.....\times 10^{-18}\; C$

(take the mass of the charge $=9.9 \times 10^{-15} kg$ and $g=10 m / s ^{2}$ )

 

  • [AIEEE 2004]
  • A

    $3.3$

  • B

    $3.2$

  • C

    $1.6$

  • D

    $4.8$

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