Due to the earth's magnetic field, charged cosmic ray particles
Due to the earth's magnetic field, charged cosmic ray particles
- [AIPMT 1997]
- A
Can never reach the equator
- B
Require less kinetic energy to reach the equator than the poles
- C
Require greater kinetic energy to reach the equator than the poles
- D
Can never reach the poles
Similar Questions
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At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ} .$ Find the true dip :
At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ} .$ Find the true dip :
- [JEE MAIN 2021]
Consider the plane $\mathrm{S}$ formed by the dipole axis and the axis of earth. Let $\mathrm{P}$ be point on the magnetic equator and in $\mathrm{S}$. Let $\mathrm{Q}$ be the point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $\mathrm{P}$ and $\mathrm{Q}$
Consider the plane $\mathrm{S}$ formed by the dipole axis and the axis of earth. Let $\mathrm{P}$ be point on the magnetic equator and in $\mathrm{S}$. Let $\mathrm{Q}$ be the point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $\mathrm{P}$ and $\mathrm{Q}$
A short magnetic needle is pivoted in a uniform magnetic field of strength $1 \,T.$ When another magnetic field of strength $\sqrt 3 \,T$ is applied to the needle in a perpendicular direction, the needle deflects through an angle $\theta$, where $\theta$ is....$^o$
A short magnetic needle is pivoted in a uniform magnetic field of strength $1 \,T.$ When another magnetic field of strength $\sqrt 3 \,T$ is applied to the needle in a perpendicular direction, the needle deflects through an angle $\theta$, where $\theta$ is....$^o$