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(A) The angle of dip $\phi$ is given by the relation $	an \phi = \frac{B_V}{B_H}$,where $B_V$ is the vertical component and $B_H$ is the horizontal c

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(A) The angle of dip $\phi$ is given by the relation $	an \phi = \frac{B_V}{B_H}$,where $B_V$ is the vertical component and $B_H$ is the horizontal component of the Earth's magnetic field.Given: $B_H = 0.30 \ G$ and $B_V = 0.173 \ G$.Substituting the values: $	an \phi = \frac{0.173}{0.30} = \frac{1.73}{3.0}$.Since $\sqrt{3} \approx 1.732$,we have $	an \phi = \frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}$.Therefore,$\phi = 	an^{-1}(\frac{1}{\sqrt{3}}) = 30^o$.

At a place,the horizontal and vertical intensities of the Earth's magnetic field are $0.30 \ G$ and $0.173 \ G$ respectively. The angle of dip at this place is.....$^o$

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