Due to the Doppler effect, the shift in wavel | vedclass

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(A) The formula for the Doppler shift in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$, where $v$ is the velocity of the sourc

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$5$

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(A) The formula for the Doppler shift in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$, where $v$ is the velocity of the source, $c$ is the speed of light, $\Delta \lambda$ is the shift in wavelength, and $\lambda$ is the original wavelength.Given: $\Delta \lambda = 0.1 	ext{ Å}$, $\lambda = 6000 	ext{ Å}$, and $c = 3 	imes 10^8 	ext{ m/s}$.Rearranging the formula to solve for $v$: $v = \frac{\Delta \lambda}{\lambda} 	imes c$.Substituting the values: $v = \frac{0.1}{6000} 	imes 3 	imes 10^8 	ext{ m/s}$.$v = \frac{1}{60000} 	imes 3 	imes 10^8 	ext{ m/s} = \frac{3 	imes 10^8}{6 	imes 10^4} 	ext{ m/s} = 0.5 	imes 10^4 	ext{ m/s} = 5000 	ext{ m/s}$.Converting to $	ext{km/s}$: $v = 5 	ext{ km/s}$.

Due to the Doppler effect, the shift in wavelength observed is $0.1 \text{ Å}$ for a star producing a wavelength of $6000 \text{ Å}$. The velocity of recession of the star will be: (in $\text{ km/s}$)

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