Light from the constellation Virgo is observe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Doppler effect for light states that the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$

Vedclass · Accepted Answer

Moving away with velocity $1.2 	imes 10^6 \ m/s$

Vedclass · Answer

(A) The Doppler effect for light states that the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$ is the relative velocity of the source and $c$ is the speed of light $(3 	imes 10^8 \ m/s)$.Since the wavelength increases (redshift),the constellation is moving away from Earth.Given $\frac{\Delta \lambda}{\lambda} = 0.4\% = 0.004$.Using the formula $v = \frac{\Delta \lambda}{\lambda} 	imes c$:$v = 0.004 	imes 3 	imes 10^8 \ m/s = 1.2 	imes 10^6 \ m/s$.Therefore,the constellation is moving away with a velocity of $1.2 	imes 10^6 \ m/s$.

Light from the constellation Virgo is observed to increase in wavelength by $0.4\%$. With respect to Earth,the constellation is:

Similar Questions

$A$ rocket is moving towards the moon with a speed $v$. The astronaut in the rocket sends signals of frequency $f$ towards the moon and receives them back after reflection from the moon. What will be the frequency of the signal received by the astronaut? (Assume $v << c$)

Write the formula for the Doppler shift for light.

The $6563 \ \mathring{A}$ line emitted by a hydrogen atom in a star is found to be red-shifted by $5 \ \mathring{A}$. The speed with which the star is receding from the Earth is:

What is the Doppler effect for light? Derive the formula for the Doppler shift.

$A$ star moves away from the Earth at a speed of $0.8\,c$ while emitting light of frequency $6 \times 10^{14} \,Hz$. What frequency will be observed on the Earth? ($c =$ speed of light)

Vedclass Test Series

Exam Paper Generator

Online Exam Module