Draw the graphs of the equations 2x + 3y = 8 | vedclass

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(D) To find the solution,we determine the points for each line:For $2x + 3y = 8$:If $x = 1, 2(1) + 3y = 8 \implies 3y = 6 \implies y = 2$. Point: $(1,

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$(1, 2)$

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(D) To find the solution,we determine the points for each line:For $2x + 3y = 8$:If $x = 1, 2(1) + 3y = 8 \implies 3y = 6 \implies y = 2$. Point: $(1, 2)$.If $x = 4, 2(4) + 3y = 8 \implies 3y = 0 \implies y = 0$. Point: $(4, 0)$.For $x + 2y = 5$:If $x = 1, 1 + 2y = 5 \implies 2y = 4 \implies y = 2$. Point: $(1, 2)$.If $x = 3, 3 + 2y = 5 \implies 2y = 2 \implies y = 1$. Point: $(3, 1)$.Since both lines pass through the point $(1, 2)$,the solution to the system of equations is $(1, 2)$.

Draw the graphs of the equations $2x + 3y = 8$ and $x + 2y = 5$ on the same graph paper. Find the solution of the system from the graph.

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