In a two-digit number,the digit at the unit's place is $3x$ and the digit at the ten's place is $2x$. Then,that number is $\ldots \ldots \ldots \ldots$

  • A
    $6x^2$
  • B
    $5x$
  • C
    $23x$
  • D
    $32x$

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If the pair of equations $\frac{5}{x} - \frac{3}{y} = 9$ and $\frac{3}{x} - \frac{5}{y} = 7$,then $\frac{1}{x} - \frac{1}{y} = \ldots$

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