Draw a graph of displacement of $SHM$ as a function of time.

The displacement $x(t)$ of a particle executing Simple Harmonic Motion $(SHM)$ is given by the equation: $x(t) = A \sin(\omega t + \phi)$,where $A$ is the amplitude,$\omega$ is the angular frequency,and $\phi$ is the initial phase constant.
Assuming the particle starts from the mean position at $t = 0$ with $\phi = 0$,the equation simplifies to $x(t) = A \sin(\omega t)$.
The graph of $x(t)$ versus $t$ is a sinusoidal wave.
$1$. At $t = 0$,$x = 0$.
$2$. At $t = T/4$,$x = A$ (maximum positive displacement).
$3$. At $t = T/2$,$x = 0$.
$4$. At $t = 3T/4$,$x = -A$ (maximum negative displacement).
$5$. At $t = T$,$x = 0$.
The graph oscillates between $+A$ and $-A$ with a period $T = 2\pi/\omega$.