The dissociation constant of a weak acid HA i | vedclass

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Question

(A) For a conjugate acid-base pair,the relationship between the dissociation constant of the acid $(K_a)$ and the dissociation constant of its conjuga

Vedclass · Accepted Answer

$5.5 	imes 10^{-11}$

Vedclass · Answer

(A) For a conjugate acid-base pair,the relationship between the dissociation constant of the acid $(K_a)$ and the dissociation constant of its conjugate base $(K_b)$ is given by the equation: $K_a 	imes K_b = K_w$. Given $K_a = 1.8 	imes 10^{-4}$ and $K_w = 1.0 	imes 10^{-14}$ at $298 \ K$. Substituting the values: $K_b = \frac{K_w}{K_a} = \frac{1.0 	imes 10^{-14}}{1.8 	imes 10^{-4}}$. $K_b = 0.555 	imes 10^{-10} = 5.55 	imes 10^{-11}$.

The dissociation constant of a weak acid $HA$ is $1.8 \times 10^{-4}$. Calculate the dissociation constant of its conjugate base $A^{-}$.

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