Dimensions of magnetic field intensity are:

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(C) The magnetic force $F$ on a current-carrying wire is given by $F = I L B \sin 	heta$.Rearranging for the magnetic field intensity $B$,we get $B =

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$[M L^0 T^{-2} A^{-1}]$

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(C) The magnetic force $F$ on a current-carrying wire is given by $F = I L B \sin 	heta$.Rearranging for the magnetic field intensity $B$,we get $B = \frac{F}{I L}$.The dimensional formula for force $F$ is $[M L T^{-2}]$.The dimensional formula for current $I$ is $[A]$.The dimensional formula for length $L$ is $[L]$.Substituting these into the formula: $B = \frac{[M L T^{-2}]}{[A] [L]} = [M L^0 T^{-2} A^{-1}]$.Thus,the correct option is $C$.

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