Out of the following,which pair of quantities | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The dimensions of the given quantities are as follows:$1$. Planck's constant $(h)$ = $[M{L^2}{T^{ - 1}}]$ and Angular momentum $(L)$ = $[M{L^2}{T^

Vedclass · Accepted Answer

Torque and moment of inertia

Vedclass · Answer

(D) The dimensions of the given quantities are as follows:$1$. Planck's constant $(h)$ = $[M{L^2}{T^{ - 1}}]$ and Angular momentum $(L)$ = $[M{L^2}{T^{ - 1}}]$. They have the same dimensions.$2$. Work $(W)$ = $[M{L^2}{T^{ - 2}}]$ and Energy $(E)$ = $[M{L^2}{T^{ - 2}}]$. They have the same dimensions.$3$. Pressure $(P)$ = $[M{L^{ - 1}}{T^{ - 2}}]$ and Young's modulus $(Y)$ = $[M{L^{ - 1}}{T^{ - 2}}]$. They have the same dimensions.$4$. Torque $(	au)$ = $[M{L^2}{T^{ - 2}}]$ and Moment of inertia $(I)$ = $[M{L^2}]$. They do not have the same dimensions.Therefore,the correct option is $D$.

Column-$1$	Column-$2$
$(a)$ Wave vector	$(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density	$(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave	$(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient	$(iv)$ $M^1L^{-1}T^0$

Out of the following,which pair of quantities does not have the same dimensions?

Similar Questions

The dimensions of pressure are

Match Column-$1$ with Column-$2$.
Column-$1$ Column-$2$
$(a)$ Wave vector $(i)$ $M^1L^0T^{-3}$
$(b)$ Linear mass density $(ii)$ $M^1L^{-1}T^{-2}$
$(c)$ Intensity of a wave $(iii)$ $M^0L^{-1}T^0$
$(d)$ Volume elasticity coefficient $(iv)$ $M^1L^{-1}T^0$

Let $[\varepsilon_0]$ be the dimensional formula of the permittivity of free space. If $M = \text{mass}$,$L = \text{length}$,$T = \text{time}$,and $A = \text{electric current}$,then which of the following is correct?

Dimensions of Gyromagnetic ratio are

Vedclass Test Series

Exam Paper Generator

Online Exam Module