(D) Linear density $m$ has dimensions of $\frac{\text{Mass}}{\text{Length}} = [ML^{-1}]$.Force $A$ has dimensions $[MLT^{-2}]$.Given the relation $A/B

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(D) Linear density $m$ has dimensions of $\frac{\text{Mass}}{\text{Length}} = [ML^{-1}]$.Force $A$ has dimensions $[MLT^{-2}]$.Given the relation $A/B = m$,we can write $B = A/m$.Substituting the dimensions: $B = \frac{[MLT^{-2}]}{[ML^{-1}]} = [L^2T^{-2}]$.Latent heat is defined as energy per unit mass: $\frac{[ML^2T^{-2}]}{[M]} = [L^2T^{-2}]$.Thus,the dimensions of $B$ are the same as those of latent heat.

Class 11 Physics Units, Dimensions and Measurement Dimensions and Dimensional Formula

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Two quantities $A$ and $B$ are related by the equation $A/B = m$,where $m$ is linear density and $A$ is force. The dimensions of $B$ are equivalent to which of the following?

A
Pressure
B
Work
C
Momentum
D
Latent heat

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Units, Dimensions and Measurement

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Dimensions and Dimensional Formula

The displacement of a progressive wave is represented by $y = A \sin(\omega t - kx)$,where $x$ is distance and $t$ is time. Write the dimensional formula of $(i)$ $\omega$ and $(ii)$ $k$.

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$A$ gas satisfies the relation $P V^{5/3} = K$,where $P$ is pressure,$V$ is volume,and $K$ is a constant. The dimensions of constant $K$ are:

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In the relation: $\frac{dy}{dx} = 2\omega \sin(\omega t + \phi_0)$,the dimensional formula for $(\omega t + \phi_0)$ is:

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The dimensions of surface tension are

Easy

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The dimensions of the universal gravitational constant are:

MediumAIPMT 2004

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Two quantities $A$ and $B$ are related by the equation $A/B = m$,where $m$ is linear density and $A$ is force. The dimensions of $B$ are equivalent to which of the following?

Similar Questions

The displacement of a progressive wave is represented by $y = A \sin(\omega t - kx)$,where $x$ is distance and $t$ is time. Write the dimensional formula of $(i)$ $\omega$ and $(ii)$ $k$.

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