Defined a vehicle can be parked on a slope.

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The velocity of the vehicle on a circular balanced road is given by,

$v_{\max }=\left[r g\left(\frac{\mu_{s}+\tan \theta}{1-\mu_{s} \tan \theta}\right)\right]^{\frac{1}{2}}$

Here we have to take $\mu_{s}=0$ as the surface is smooth.

$v_{\max }=\left[\operatorname{rg}\left(\frac{0+\tan \theta}{1-0}\right)\right]^{\frac{1}{2}}$

$\therefore v_{\max } =\left[r g\left(\frac{\tan \theta}{1}\right)\right]^{-}$

$\therefore v_{\max } =\sqrt{r g \tan \theta}$

At this speed, frictional force is not needed at all to provide the necessary centripetal force. Driving at this speed on a banked road will cause little wear and tear on the tyres. $v_{0}$ is called the optimum speed.

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