A particle is describing circular motion in a | vedclass

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Question

As $\mathrm{N} \sin \alpha=\mathrm{mg}$

$\mathrm{N} \cos \alpha=\mathrm{m} \omega^{2} \mathrm{r}$

$	an \alpha=\frac{g}{\omega^{2} r}$

$	her

Vedclass · Accepted Answer

increases as $h$ increases keeping $\alpha $ same

Vedclass · Answer

As $\mathrm{N} \sin \alpha=\mathrm{mg}$

$\mathrm{N} \cos \alpha=\mathrm{m} \omega^{2} \mathrm{r}$

$	an \alpha=\frac{g}{\omega^{2} r}$

$	herefore \mathrm{T}^{2} \propto \mathrm{r} 	an \alpha$

$	herefore \mathrm{T}^{2} \propto \mathrm{h} 	an ^{2} \alpha$

for constant $\alpha$

$\mathrm{T}^{2} \propto \mathrm{h}$

Thus when $h$ increases $T$ also increases

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