Define mole. Give its symbol. What is the advantage of this mole concept?
(N/A) mole of particles (atoms,ions,or molecules) is defined as the amount of a substance that contains the same number of particles as there are in $12 \ g$ of the $C-12$ isotope.
Experimentally,it has been found that $0.012 \ kg$ of carbon-$12$ contains $6.022 \times 10^{23}$ atoms. This number is called Avogadro's number or Avogadro's constant and is represented by the symbol $N_A$ or $N_0$.
The symbol for the unit of mole is $mol$.
Advantage of the Mole Concept:
The mole concept allows for the convenient selection of a specific number of atoms and molecules by relating them to the mass and volume of a chemical substance,making stoichiometric calculations easier.
Experimentally,it has been found that $0.012 \ kg$ of carbon-$12$ contains $6.022 \times 10^{23}$ atoms. This number is called Avogadro's number or Avogadro's constant and is represented by the symbol $N_A$ or $N_0$.
The symbol for the unit of mole is $mol$.
Advantage of the Mole Concept:
The mole concept allows for the convenient selection of a specific number of atoms and molecules by relating them to the mass and volume of a chemical substance,making stoichiometric calculations easier.
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$(i)$ Name the body which approves the nomenclature of elements and compounds.
$(ii)$ The symbol of sodium is written as $Na$ and not as $S$. Give reason.
$(iii)$ Name one element which forms diatomic and one which forms tetraatomic molecules.
$(ii)$ The symbol of sodium is written as $Na$ and not as $S$. Give reason.
$(iii)$ Name one element which forms diatomic and one which forms tetraatomic molecules.
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$(b)$ Carbon dioxide
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$(a)$ Methane
$(b)$ Carbon dioxide
$(c)$ Hydrogen sulphide
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$(b)$ Calculate the number of molecules of glucose present in its $90 \ g$ (molecular mass of glucose is $180 \ u$). (Avogadro constant $= 6.022 \times 10^{23} \ mol^{-1}$)
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$(c)$ Calculate the number of moles of water in $2 \ g$ of water.
(Atomic mass of $H = 1 \ u, O = 16 \ u$)
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The atomicity of phosphorus is $5$ and that of sulphur is $6$.
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