The correct option$(s)$ for the following sequence of reactions is(are):
$(A)$ $Q = KNO_2, W = LiAlH_4$
$(B)$ $R =$ benzenamine,$V = KCN$
$(C)$ $Q = AgNO_2, R =$ phenylmethanamine
$(D)$ $W = LiAlH_4, V = AgCN$

What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

Match each of the compounds in Column $I$ with its characteristic reaction$(s)$ in Column $II$.

Column $I$	Column $II$
$A$. $CH_3CH_2CH_2CN$	$p$. Reduction with $Pd-C/H_2$
$B$. $CH_3CH_2OCOCH_3$	$q$. Reduction with $SnCl_2/HCl$
$C$. $CH_3-CH=CH-CH_2OH$	$r$. Development of foul smell on treatment with chloroform and alcoholic $KOH$
$D$. $CH_3CH_2CH_2CH_2NH_2$	$s$. Reduction with diisobutylaluminium hydride $(DIBAL-H)$
	$t$. Alkaline hydrolysis

Consider the following sequence of reactions to produce major product $(A)$. Molar mass of product $(A)$ is $........... \ g \ mol^{-1}$. (Given molar mass in $g \ mol^{-1}$ of $C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31$)

Consider the following sequence of reactions:
Chlorobenzene $\xrightarrow[ii) CO_2, H_3O^{+}]{i) Mg, \text{dry ether}} \text{Benzoic acid}$ $\xrightarrow{NH_3, \Delta} \text{Benzamide (A)}$ $\xrightarrow{Br_2, NaOH} \text{Aniline (B)}$
$11.25 \ mg$ of chlorobenzene will produce $.......... \times 10^{-1} \ mg$ of product $B$.
(Consider the reactions result in complete conversion.)
[Given molar mass of $C, H, O, N$ and $Cl$ as $12, 1, 16, 14$ and $35.5 \ g \ mol^{-1}$ respectively]

An organic compound $A$ reacts with $NH_3$ on heating to give $B$. Compound $B$ reacts with $Br_2$ in the presence of $KOH$ to give $CH_3CH_2NH_2$. What is $A$?