What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

You have been given four bottles marked $A, B, C$ and $D$ each containing one of the organic compounds given below:

$I: C_6H_5CH_2NH_2$	$II: C_6H_5CH_2COOH$
$III: C_6H_5CH_2CH_3$	$IV: C_6H_5CH_2CH(NH_2)COOH$

The following observations were made:
$(i)$ The compound in bottle $A$ did not dissolve in either $1 \ N \ NaOH$ or $1 \ N \ HCl$.
$(ii)$ The compound in bottle $B$ dissolved in $1 \ N \ NaOH$ but not in $1 \ N \ HCl$.
$(iii)$ The compound in bottle $C$ dissolved in both $1 \ N \ NaOH$ and $1 \ N \ HCl$.
$(iv)$ The compound in bottle $D$ did not dissolve in $1 \ N \ NaOH$ but dissolved in $1 \ N \ HCl$.
$(a)$ Indicate the compounds in: bottle $A = \dots$,bottle $B = \dots$,bottle $C = \dots$ and bottle $D = \dots$.
$(b)$ The compound with the highest solubility in distilled water is .......

How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?

The ammonolysis of alcohol is represented by the reaction $xCH_3OH + yNH_3 \xrightarrow[Al_2O_3/ThO_2]{300-400^{\circ}C} \text{Products}$. The products formed are:

Which one of the following methods is neither meant for the synthesis nor for separation of amines?

The product $(B)$ is: