Consider the plane $\mathrm{S}$ formed by the dipole axis and the axis of earth. Let $\mathrm{P}$ be point on the magnetic equator and in $\mathrm{S}$. Let $\mathrm{Q}$ be the point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $\mathrm{P}$ and $\mathrm{Q}$
Let point $\mathrm{P}$ is in the plane $\mathrm{S}$, needle is in north, so the declination is zero.
Since point $P$ lies in plane $S$ formed by the dipole axis and the axis of the Earth, declination is zero. Since point Q lies on the magnetic equator angle of dip is zero.
It is $11.3^{\circ}$ tilted with its axis of the earth so declination between $P$ and $Q$ is $11.3^{\circ}$.
At an angle of $30^{\circ}$ to the magnetic meridian, the apparent dip is $45^{\circ} .$ Find the true dip :
Define angle of dip. and Write the definition of declination.
Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of $3\,s$ and $4\,s$ respectively. If their moments of inertia are in the ratio of $3: 2$ then the ratio of their magnetic moments will e.
If the dip circle is set at $45^o$ to the magnetic meridian, then the apparent dip is $30^o$. The true dip. of the place is
Planets producing larger magnetic field have larger