Consider the function f: [1.2, 1.9] rightarro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For $x \in [1.2, 1.9]$,the greatest integer function $[x]$ is constant because $1 \le x < 2$. Specifically,for any $x$ in the interval $[1.2, 1.9]

Vedclass · Accepted Answer

$f'(x) = 0$

Vedclass · Answer

(A) For $x \in [1.2, 1.9]$,the greatest integer function $[x]$ is constant because $1 \le x Specifically,for any $x$ in the interval $[1.2, 1.9]$,$[x] = 1$. Since $f(x) = 1$ is a constant function on the interval $[1.2, 1.9]$,it is continuous and differentiable at every point in the interval. The derivative of a constant function is zero,so $f'(x) = 0$ for all $x \in [1.2, 1.9]$. Therefore,option $A$ is correct.

Consider the function $f: [1.2, 1.9] \rightarrow \mathbb{R}$ defined by $f(x) = [x]$,where $[x]$ denotes the greatest integer less than or equal to $x$. Which of the following is true?

Similar Questions

If $y = f \left( \frac{3x + 4}{5x + 6} \right)$ and $f'(x) = \tan(x^2)$,then $\frac{dy}{dx} = $

If $y = x + \frac{1}{x}$,then

$A$ function $f$ satisfying $f'( \sin x ) = \cos^2 x$ for all $x$ and $f(1) = 1$ is :

If $3 f(x)-2 f\left(\frac{1}{x}\right)=x$,then $f^{\prime}(2)=$

If $a$ and $b$ are fixed non-zero constants,then the derivative of $\frac{a}{x^{4}}-\frac{b}{x^{2}}+\cos x$ is $ma+nb-p$,where

Vedclass Test Series

Exam Paper Generator

Online Exam Module