Consider the following: (I) CH_3CH_2NH_2 (II) | vedclass

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(B) In ethylamine $(I)$,the $+I$ effect of the ethyl group increases the electron density on the nitrogen atom,making it the strongest base. In benzyl

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$I > II > III$

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(B) In ethylamine $(I)$,the $+I$ effect of the ethyl group increases the electron density on the nitrogen atom,making it the strongest base. In benzylamine $(II)$,the phenyl group exerts a $-I$ effect,which decreases the electron density on the nitrogen atom compared to ethylamine,but the lone pair is not involved in resonance with the ring. In aniline $(III)$,the lone pair on the nitrogen atom is delocalized into the benzene ring due to resonance,which significantly reduces the availability of the lone pair for protonation,making it the weakest base. Therefore,the correct order of basic strength is $I > II > III$.

Consider the following:
$(I)$ $CH_3CH_2NH_2$
$(II)$ $PhCH_2NH_2$
$(III)$ $PhNH_2$
The correct order of their basic strength is:

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Consider the following: $(I)$ $CH_3CH_2NH_2$ $(II)$ $PhCH_2NH_2$ $(III)$ $PhNH_2$ The correct order of their basic strength is: