Consider the following two statements:A. The | vedclass

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(D) In $\alpha-$ decay,the parent nucleus decays into a daughter nucleus and an $\alpha-$ particle. Due to the conservation of energy and momentum,the

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Both $A$ and $B$ are correct.

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(D) In $\alpha-$ decay,the parent nucleus decays into a daughter nucleus and an $\alpha-$ particle. Due to the conservation of energy and momentum,the $\alpha-$ particle must carry a specific,fixed amount of energy,resulting in a discrete energy spectrum.In $\beta-$ decay,the energy released is shared between the $\beta-$ particle (electron or positron) and an antineutrino (or neutrino). Since the energy can be shared in infinitely many ways between these two particles,the energy spectrum of the emitted $\beta-$ particles is continuous.Therefore,statement $A$ is incorrect (as it claims the spectrum is discrete,but $\alpha-$ decay is discrete,wait,let's re-evaluate: $\alpha-$ decay is indeed discrete,so $A$ is correct. $\beta-$ decay is continuous,so $B$ is correct). Both statements are correct.

Consider the following two statements:
$A.$ The energy spectrum of $\alpha-$ particles emitted in radioactive decay is discrete.
$B.$ The energy spectrum of $\beta-$ particles emitted in radioactive decay is continuous.

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Consider the following two statements:$A.$ The energy spectrum of $\alpha-$ particles emitted in radioactive decay is discrete.$B.$ The energy spectrum of $\beta-$ particles emitted in radioactive decay is continuous.