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(D) The Maxwell-Boltzmann distribution curve shows the fraction of molecules versus kinetic energy. When the temperature is increased,the peak of the

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Area $I$ would decrease and area $II$ would increase

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(D) The Maxwell-Boltzmann distribution curve shows the fraction of molecules versus kinetic energy. When the temperature is increased,the peak of the curve shifts to the right and the height of the peak decreases,while the curve flattens out. Area $II$ represents the fraction of molecules with kinetic energy greater than the activation energy $(E_a)$. As the temperature increases,a larger fraction of molecules possess kinetic energy equal to or greater than $E_a$,so area $II$ increases. Since the total area under the curve must remain constant (equal to $1$),and area $II$ increases,the remaining area (area $I$) must decrease to compensate for the increase in area $II$.

Consider the following graph of the kinetic energy distribution among molecules at temperature $T.$ If the temperature is increased,how would the resulting graph differ from the one above $:-$

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